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**careless25****Real Member**- Registered: 2008-07-24
- Posts: 560

Yea so my logic is that the first card will always be 100% correct, the next card has a probability of 36/51, and the third will be 22/50, but the fourth has to be the compliment so 42/49. Does that make sense?

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

No, hold on one second. You have not given all the rules. What is a 3 card badugi?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**careless25****Real Member**- Registered: 2008-07-24
- Posts: 560

Ok so basically you are dealt 4 cards, out of the 4 cards, 3 of them have different suits and different values but the last one is either the same suit/value as one of the three. What are the odds of this?

I think you misread the question before.

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

What about a 3 card badugi. Are you saying it does not matter if some of them are badugis?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**careless25****Real Member**- Registered: 2008-07-24
- Posts: 560

There is never a 3 card badugi, for a badugi you need 4 cards with 4 different suits and values.

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**careless25****Real Member**- Registered: 2008-07-24
- Posts: 560

In other words, you are one card away from a Badugi. This is fairly tricky, so be careful with the counting here. The correct answer is between 55% and 60%.

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Okay, I will work on it and post when I have something.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**careless25****Real Member**- Registered: 2008-07-24
- Posts: 560

Hahaha I knew I was right about the balls and slots, I was just mixing up the variables

Where n is the number of letters and k is the number of slots. We learned the right side of the equation in class so I am more accustomed to that, I just have to figure out which variable is which.

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**gAr****Member**- Registered: 2011-01-09
- Posts: 3,482

Hi all,

Let me check whether I understood it correct.

First, I'll calculate the number of ways to get a badugi:

52*38*24*10 ways

Do we agree?

"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?

"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi gAr;

That is a little off.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**gAr****Member**- Registered: 2011-01-09
- Posts: 3,482

Hmmm, what went wrong?

"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?

"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

It is very difficult to do it that way. I always seem to leave someone out. The right answer I think is 52 * 36 * 22 * 10 another way

is

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**gAr****Member**- Registered: 2011-01-09
- Posts: 3,482

Hi,

I don't understand.

First card can be any: 52

Second card the different suit, and different value: 52 - 13 -1 = 38

Third : 52 - 26 - 2 = 24

Fourth : 52 - 39 - 3 = 10

Something wrong here?

"Believe nothing, no matter where you read it, or who said it, no matter if I have said it, unless it agrees with your own reason and your own common sense" - Buddha?

"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."

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**careless25****Real Member**- Registered: 2008-07-24
- Posts: 560

Hi gAr!

Its actually

second card: different sut different VALUE so 52 - 13 - 3 = 36

third card: 52-26 - 4 = 22

*Last edited by careless25 (2011-05-29 23:51:35)*

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**careless25****Real Member**- Registered: 2008-07-24
- Posts: 560

AHHH!! HAHAHA Bobbym i am pretty sure that is not the right answer....remember the hint: it is between 55% and 60%...ur answer is 6.3%

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

What answer, I have no answer so far.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**careless25****Real Member**- Registered: 2008-07-24
- Posts: 560

Oh! I thot

was wat your answer was.Nvm that is actually correct and agrees with my answer for the probability of getting a badugi.

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Yes, that is for a badugi. I was just showing a simpler way for gAr.

How do you know the 3 card problem is 55% - 60%?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**careless25****Real Member**- Registered: 2008-07-24
- Posts: 560

That was stated in the question. (I did not post it when i posted the question)

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**careless25****Real Member**- Registered: 2008-07-24
- Posts: 560

3 cases:

1. diff value, same suit as one card

2. diff suit, same value as one card

3. same suit, same value with another card

Final answer:

make sense???

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**gAr****Member**- Registered: 2011-01-09
- Posts: 3,482

Hi all,

The answer I get is :

52*36*24*39 / (52*51*50*49)

I get the same by direct counting also.

"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."

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**gAr****Member**- Registered: 2011-01-09
- Posts: 3,482

Hi,

We can consider only 2 cases:

1)

Fourth card is of one of the suites already there:

52*36*24* (36)

2)

Fourth card is of the other remaining suit:

52*36*24* (3)

Hence 1) + 2) = 52*36*24* (36+3) ways

"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

Hi;

That is what I got but he said it was between 55% and 60% which I do not yet understand.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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**gAr****Member**- Registered: 2011-01-09
- Posts: 3,482

Hi bobbym,

Since computer too verifies it, I guess 55-60% must be a mistake, or the question is incomplete.

"Data! Data! Data!" he cried impatiently. "I can't make bricks without clay."

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**bobbym****bumpkin**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606

That is what I was thinking.

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.**** Always satisfy the Prime Directive of getting the right answer above all else.**

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